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142164405255617 is a prime number
BaseRepresentation
bin100000010100110000111010…
…110111111111110111000001
3200122100210011211120201012122
4200110300322313333313001
5122113210200221134432
61222205232015134025
741642016330305153
oct4024607267776701
9618323154521178
10142164405255617
1141330649603a08
1213b404b7814315
136143079a948c4
142716b18776ad3
151168050a7c612
hex814c3adffdc1

142164405255617 has 2 divisors, whose sum is σ = 142164405255618. Its totient is φ = 142164405255616.

The previous prime is 142164405255571. The next prime is 142164405255641. The reversal of 142164405255617 is 716552504461241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94265147032576 + 47899258223041 = 9709024^2 + 6920929^2 .

It is a cyclic number.

It is not a de Polignac number, because 142164405255617 - 212 = 142164405251521 is a prime.

It is a super-2 number, since 2×1421644052556172 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (142164405255647) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71082202627808 + 71082202627809.

It is an arithmetic number, because the mean of its divisors is an integer number (71082202627809).

Almost surely, 2142164405255617 is an apocalyptic number.

It is an amenable number.

142164405255617 is a deficient number, since it is larger than the sum of its proper divisors (1).

142164405255617 is an equidigital number, since it uses as much as digits as its factorization.

142164405255617 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064000, while the sum is 53.

The spelling of 142164405255617 in words is "one hundred forty-two trillion, one hundred sixty-four billion, four hundred five million, two hundred fifty-five thousand, six hundred seventeen".