14219041473953 has 2 divisors, whose sum is σ = 14219041473954. Its totient is φ = 14219041473952.

The previous prime is 14219041473821. The next prime is 14219041474013. The reversal of 14219041473953 is 35937414091241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13221535916449 + 997505557504 = 3636143^2 + 998752^2 .

It is a cyclic number.

It is not a de Polignac number, because 14219041473953 - 2²⁸ = 14218773038497 is a prime.

It is a super-2 number, since 2×14219041473953² (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14219041473895 and 14219041473904.

It is not a weakly prime, because it can be changed into another prime (14219041478953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7109520736976 + 7109520736977.

It is an arithmetic number, because the mean of its divisors is an integer number (7109520736977).

Almost surely, 2^{14219041473953} is an apocalyptic number.

It is an amenable number.

14219041473953 is a deficient number, since it is larger than the sum of its proper divisors (1).

14219041473953 is an equidigital number, since it uses as much as digits as its factorization.

14219041473953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3265920, while the sum is 53.

The spelling of 14219041473953 in words is "fourteen trillion, two hundred nineteen billion, forty-one million, four hundred seventy-three thousand, nine hundred fifty-three".