Base | Representation |
---|---|
bin | 1100111011101110000101… |
… | …1100111110111101111111 |
3 | 1212100102121220111000002222 |
4 | 3032323201130332331333 |
5 | 3330440303300040221 |
6 | 50124345045035555 |
7 | 2665240635353531 |
oct | 316734134767577 |
9 | 55312556430088 |
10 | 14220124221311 |
11 | 45927a2450148 |
12 | 1717b569b5bbb |
13 | 7c1c4b5c2188 |
14 | 37238712d851 |
15 | 199d70e799ab |
hex | ceee173ef7f |
14220124221311 has 2 divisors, whose sum is σ = 14220124221312. Its totient is φ = 14220124221310.
The previous prime is 14220124221263. The next prime is 14220124221319. The reversal of 14220124221311 is 11312242102241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14220124221311 - 222 = 14220120027007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14220124221319) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7110062110655 + 7110062110656.
It is an arithmetic number, because the mean of its divisors is an integer number (7110062110656).
Almost surely, 214220124221311 is an apocalyptic number.
14220124221311 is a deficient number, since it is larger than the sum of its proper divisors (1).
14220124221311 is an equidigital number, since it uses as much as digits as its factorization.
14220124221311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 14220124221311 its reverse (11312242102241), we get a palindrome (25532366323552).
The spelling of 14220124221311 in words is "fourteen trillion, two hundred twenty billion, one hundred twenty-four million, two hundred twenty-one thousand, three hundred eleven".
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