Base | Representation |
---|---|
bin | 1100111011101110001000… |
… | …0011100011001101010111 |
3 | 1212100102122121111122022011 |
4 | 3032323202003203031113 |
5 | 3330440313342044343 |
6 | 50124350045445051 |
7 | 2665241120321512 |
oct | 316734203431527 |
9 | 55312577448264 |
10 | 14220134331223 |
11 | 45927a8125947 |
12 | 1717b5a270787 |
13 | 7c1c50721a82 |
14 | 372388601d79 |
15 | 199d71cc529d |
hex | ceee20e3357 |
14220134331223 has 2 divisors, whose sum is σ = 14220134331224. Its totient is φ = 14220134331222.
The previous prime is 14220134331187. The next prime is 14220134331233. The reversal of 14220134331223 is 32213343102241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14220134331223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14220134331233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7110067165611 + 7110067165612.
It is an arithmetic number, because the mean of its divisors is an integer number (7110067165612).
Almost surely, 214220134331223 is an apocalyptic number.
14220134331223 is a deficient number, since it is larger than the sum of its proper divisors (1).
14220134331223 is an equidigital number, since it uses as much as digits as its factorization.
14220134331223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 14220134331223 its reverse (32213343102241), we get a palindrome (46433477433464).
The spelling of 14220134331223 in words is "fourteen trillion, two hundred twenty billion, one hundred thirty-four million, three hundred thirty-one thousand, two hundred twenty-three".
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