Base | Representation |
---|---|
bin | 1000010001110100001… |
… | …1101000001110110011 |
3 | 111121002122200021002222 |
4 | 2010131003220032303 |
5 | 4312232140130001 |
6 | 145200254231255 |
7 | 13163244022643 |
oct | 2043503501663 |
9 | 447078607088 |
10 | 142221411251 |
11 | 55352308307 |
12 | 236917b552b |
13 | 10546b7c21a |
14 | 6c52680523 |
15 | 3a75c6c61b |
hex | 211d0e83b3 |
142221411251 has 2 divisors, whose sum is σ = 142221411252. Its totient is φ = 142221411250.
The previous prime is 142221411247. The next prime is 142221411253. The reversal of 142221411251 is 152114122241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142221411251 - 22 = 142221411247 is a prime.
Together with 142221411253, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 142221411251.
It is not a weakly prime, because it can be changed into another prime (142221411253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71110705625 + 71110705626.
It is an arithmetic number, because the mean of its divisors is an integer number (71110705626).
Almost surely, 2142221411251 is an apocalyptic number.
142221411251 is a deficient number, since it is larger than the sum of its proper divisors (1).
142221411251 is an equidigital number, since it uses as much as digits as its factorization.
142221411251 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1280, while the sum is 26.
Adding to 142221411251 its reverse (152114122241), we get a palindrome (294335533492).
The spelling of 142221411251 in words is "one hundred forty-two billion, two hundred twenty-one million, four hundred eleven thousand, two hundred fifty-one".
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