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142221411251 is a prime number
BaseRepresentation
bin1000010001110100001…
…1101000001110110011
3111121002122200021002222
42010131003220032303
54312232140130001
6145200254231255
713163244022643
oct2043503501663
9447078607088
10142221411251
1155352308307
12236917b552b
1310546b7c21a
146c52680523
153a75c6c61b
hex211d0e83b3

142221411251 has 2 divisors, whose sum is σ = 142221411252. Its totient is φ = 142221411250.

The previous prime is 142221411247. The next prime is 142221411253. The reversal of 142221411251 is 152114122241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 142221411251 - 22 = 142221411247 is a prime.

Together with 142221411253, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 142221411251.

It is not a weakly prime, because it can be changed into another prime (142221411253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71110705625 + 71110705626.

It is an arithmetic number, because the mean of its divisors is an integer number (71110705626).

Almost surely, 2142221411251 is an apocalyptic number.

142221411251 is a deficient number, since it is larger than the sum of its proper divisors (1).

142221411251 is an equidigital number, since it uses as much as digits as its factorization.

142221411251 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1280, while the sum is 26.

Adding to 142221411251 its reverse (152114122241), we get a palindrome (294335533492).

The spelling of 142221411251 in words is "one hundred forty-two billion, two hundred twenty-one million, four hundred eleven thousand, two hundred fifty-one".