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1422250211014 = 2711125105507
BaseRepresentation
bin10100101100100100101…
…101111111011011000110
312000222002001200121221021
4110230210231333123012
5141300232023223024
63005212301541354
7204516454216633
oct24544455773306
95028061617837
101422250211014
114a919a191136
121ab78487485a
13a416b5435c9
144cba16bd18a
1526ee1714de4
hex14b24b7f6c6

1422250211014 has 4 divisors (see below), whose sum is σ = 2133375316524. Its totient is φ = 711125105506.

The previous prime is 1422250211003. The next prime is 1422250211021. The reversal of 1422250211014 is 4101120522241.

It is a semiprime because it is the product of two primes.

It is a super-4 number, since 4×14222502110144 (a number of 50 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1422250211014.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 355562552752 + ... + 355562552755.

It is an arithmetic number, because the mean of its divisors is an integer number (533343829131).

Almost surely, 21422250211014 is an apocalyptic number.

1422250211014 is a deficient number, since it is larger than the sum of its proper divisors (711125105510).

1422250211014 is an equidigital number, since it uses as much as digits as its factorization.

1422250211014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 711125105509.

The product of its (nonzero) digits is 1280, while the sum is 25.

Adding to 1422250211014 its reverse (4101120522241), we get a palindrome (5523370733255).

The spelling of 1422250211014 in words is "one trillion, four hundred twenty-two billion, two hundred fifty million, two hundred eleven thousand, fourteen".

Divisors: 1 2 711125105507 1422250211014