Base | Representation |
---|---|
bin | 10100101100100100111… |
… | …110000101111110001111 |
3 | 12000222002100122002020101 |
4 | 110230210332011332033 |
5 | 141300234113312033 |
6 | 3005212532231531 |
7 | 204516535130266 |
oct | 24544476057617 |
9 | 5028070562211 |
10 | 1422254432143 |
11 | 4a91a1604576 |
12 | 1ab78616b5a7 |
13 | a416c390a0c |
14 | 4cba209b5dd |
15 | 26ee1c9a97d |
hex | 14b24f85f8f |
1422254432143 has 2 divisors, whose sum is σ = 1422254432144. Its totient is φ = 1422254432142.
The previous prime is 1422254432117. The next prime is 1422254432177. The reversal of 1422254432143 is 3412344522241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1422254432143 - 25 = 1422254432111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1422254436143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711127216071 + 711127216072.
It is an arithmetic number, because the mean of its divisors is an integer number (711127216072).
Almost surely, 21422254432143 is an apocalyptic number.
1422254432143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1422254432143 is an equidigital number, since it uses as much as digits as its factorization.
1422254432143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 184320, while the sum is 37.
Adding to 1422254432143 its reverse (3412344522241), we get a palindrome (4834598954384).
The spelling of 1422254432143 in words is "one trillion, four hundred twenty-two billion, two hundred fifty-four million, four hundred thirty-two thousand, one hundred forty-three".
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