Base | Representation |
---|---|
bin | 1100111011111000111101… |
… | …0000001011101111001101 |
3 | 1212100201011010020001112001 |
4 | 3032332033100023233031 |
5 | 3331012241231220300 |
6 | 50125550250312301 |
7 | 2665403123053456 |
oct | 316761720135715 |
9 | 55321133201461 |
10 | 14223040101325 |
11 | 4593a59385a40 |
12 | 171862b428691 |
13 | 7c22c4732c73 |
14 | 3725824ba12d |
15 | 199e91e5416a |
hex | cef8f40bbcd |
14223040101325 has 96 divisors (see below), whose sum is σ = 21265241223168. Its totient is φ = 9317140992000.
The previous prime is 14223040101317. The next prime is 14223040101337. The reversal of 14223040101325 is 52310104032241.
It is not a de Polignac number, because 14223040101325 - 23 = 14223040101317 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14223040101293 and 14223040101302.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 9877492 + ... + 11225458.
It is an arithmetic number, because the mean of its divisors is an integer number (221512929408).
Almost surely, 214223040101325 is an apocalyptic number.
It is an amenable number.
14223040101325 is a deficient number, since it is larger than the sum of its proper divisors (7042201121843).
14223040101325 is a wasteful number, since it uses less digits than its factorization.
14223040101325 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1348103 (or 1348098 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 14223040101325 its reverse (52310104032241), we get a palindrome (66533144133566).
The spelling of 14223040101325 in words is "fourteen trillion, two hundred twenty-three billion, forty million, one hundred one thousand, three hundred twenty-five".
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