Base | Representation |
---|---|
bin | 1100111011111001001100… |
… | …0111110101110000100011 |
3 | 1212100201022122101102022221 |
4 | 3032332103013311300203 |
5 | 3331012404341214021 |
6 | 50130000530011511 |
7 | 2665404541636513 |
oct | 316762307656043 |
9 | 55321278342287 |
10 | 14223105023011 |
11 | 4593a91a98625 |
12 | 1718649116b97 |
13 | 7c2305014171 |
14 | 37258ad79843 |
15 | 199e979ca241 |
hex | cef931f5c23 |
14223105023011 has 2 divisors, whose sum is σ = 14223105023012. Its totient is φ = 14223105023010.
The previous prime is 14223105022993. The next prime is 14223105023069. The reversal of 14223105023011 is 11032050132241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14223105023011 - 27 = 14223105022883 is a prime.
It is a super-3 number, since 3×142231050230113 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (14223105003011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111552511505 + 7111552511506.
It is an arithmetic number, because the mean of its divisors is an integer number (7111552511506).
Almost surely, 214223105023011 is an apocalyptic number.
14223105023011 is a deficient number, since it is larger than the sum of its proper divisors (1).
14223105023011 is an equidigital number, since it uses as much as digits as its factorization.
14223105023011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 14223105023011 its reverse (11032050132241), we get a palindrome (25255155155252).
The spelling of 14223105023011 in words is "fourteen trillion, two hundred twenty-three billion, one hundred five million, twenty-three thousand, eleven".
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