Base | Representation |
---|---|
bin | 1100111011111001100011… |
… | …1010010101000100000001 |
3 | 1212100201120102010200222121 |
4 | 3032332120322111010001 |
5 | 3331013104222111023 |
6 | 50130014315404241 |
7 | 2665410131312545 |
oct | 316763072250401 |
9 | 55321512120877 |
10 | 14223202144513 |
11 | 45940318a342a |
12 | 1718675753681 |
13 | 7c231c18a6cb |
14 | 372599c1ba25 |
15 | 199ea12b1d5d |
hex | cef98e95101 |
14223202144513 has 2 divisors, whose sum is σ = 14223202144514. Its totient is φ = 14223202144512.
The previous prime is 14223202144439. The next prime is 14223202144523. The reversal of 14223202144513 is 31544120232241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13921084823409 + 302117321104 = 3731097^2 + 549652^2 .
It is a cyclic number.
It is not a de Polignac number, because 14223202144513 - 29 = 14223202144001 is a prime.
It is not a weakly prime, because it can be changed into another prime (14223202144523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111601072256 + 7111601072257.
It is an arithmetic number, because the mean of its divisors is an integer number (7111601072257).
Almost surely, 214223202144513 is an apocalyptic number.
It is an amenable number.
14223202144513 is a deficient number, since it is larger than the sum of its proper divisors (1).
14223202144513 is an equidigital number, since it uses as much as digits as its factorization.
14223202144513 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 14223202144513 its reverse (31544120232241), we get a palindrome (45767322376754).
The spelling of 14223202144513 in words is "fourteen trillion, two hundred twenty-three billion, two hundred two million, one hundred forty-four thousand, five hundred thirteen".
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