Base | Representation |
---|---|
bin | 1100111011111010011100… |
… | …0111001101001010000111 |
3 | 1212100202012000110101111002 |
4 | 3032332213013031022013 |
5 | 3331014101220313111 |
6 | 50130054110203515 |
7 | 2665416053414141 |
oct | 316764707151207 |
9 | 55322160411432 |
10 | 14223440401031 |
11 | 4594144336044 |
12 | 17187214b359b |
13 | 7c235964aab4 |
14 | 3725bd71bc91 |
15 | 199eb717663b |
hex | cefa71cd287 |
14223440401031 has 2 divisors, whose sum is σ = 14223440401032. Its totient is φ = 14223440401030.
The previous prime is 14223440400919. The next prime is 14223440401057. The reversal of 14223440401031 is 13010404432241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14223440401031 is a prime.
It is a super-2 number, since 2×142234404010312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14223440400985 and 14223440401003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14223440401231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111720200515 + 7111720200516.
It is an arithmetic number, because the mean of its divisors is an integer number (7111720200516).
Almost surely, 214223440401031 is an apocalyptic number.
14223440401031 is a deficient number, since it is larger than the sum of its proper divisors (1).
14223440401031 is an equidigital number, since it uses as much as digits as its factorization.
14223440401031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 14223440401031 its reverse (13010404432241), we get a palindrome (27233844833272).
The spelling of 14223440401031 in words is "fourteen trillion, two hundred twenty-three billion, four hundred forty million, four hundred one thousand, thirty-one".
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