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142234412303443 is a prime number
BaseRepresentation
bin100000010101110010000111…
…100111101100010001010011
3200122121110212202012012212211
4200111302013213230101103
5122120332034022202233
61222301330441132551
741650045221350335
oct4025620747542123
9618543782165784
10142234412303443
114135830377a129
1213b51b94a8a157
136149855809165
14271a27a2a5455
151169c9bad15cd
hex815c879ec453

142234412303443 has 2 divisors, whose sum is σ = 142234412303444. Its totient is φ = 142234412303442.

The previous prime is 142234412303429. The next prime is 142234412303447. The reversal of 142234412303443 is 344303214432241.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (344303214432241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142234412303443 - 213 = 142234412295251 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 142234412303396 and 142234412303405.

It is not a weakly prime, because it can be changed into another prime (142234412303447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71117206151721 + 71117206151722.

It is an arithmetic number, because the mean of its divisors is an integer number (71117206151722).

Almost surely, 2142234412303443 is an apocalyptic number.

142234412303443 is a deficient number, since it is larger than the sum of its proper divisors (1).

142234412303443 is an equidigital number, since it uses as much as digits as its factorization.

142234412303443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 663552, while the sum is 40.

Adding to 142234412303443 its reverse (344303214432241), we get a palindrome (486537626735684).

The spelling of 142234412303443 in words is "one hundred forty-two trillion, two hundred thirty-four billion, four hundred twelve million, three hundred three thousand, four hundred forty-three".