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14224044401339 is a prime number
BaseRepresentation
bin1100111011111100101100…
…0111010010001010111011
31212100210202002222210010212
43032333023013102022323
53331021320331320324
650130234044101335
72665440036344033
oct316771307221273
955323662883125
1014224044401339
114594424276453
12171886b83484b
137c2424817426
14372639a268c3
1519a0001d470e
hexcefcb1d22bb

14224044401339 has 2 divisors, whose sum is σ = 14224044401340. Its totient is φ = 14224044401338.

The previous prime is 14224044401297. The next prime is 14224044401341. The reversal of 14224044401339 is 93310444042241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14224044401339 is a prime.

Together with 14224044401341, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14224044401296 and 14224044401305.

It is not a weakly prime, because it can be changed into another prime (14224044406339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112022200669 + 7112022200670.

It is an arithmetic number, because the mean of its divisors is an integer number (7112022200670).

Almost surely, 214224044401339 is an apocalyptic number.

14224044401339 is a deficient number, since it is larger than the sum of its proper divisors (1).

14224044401339 is an equidigital number, since it uses as much as digits as its factorization.

14224044401339 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 331776, while the sum is 41.

The spelling of 14224044401339 in words is "fourteen trillion, two hundred twenty-four billion, forty-four million, four hundred one thousand, three hundred thirty-nine".