Base | Representation |
---|---|
bin | 1100111011111100111001… |
… | …1011111010010110001011 |
3 | 1212100210212222212121210112 |
4 | 3032333032123322112023 |
5 | 3331021424113443202 |
6 | 50130243354504535 |
7 | 2665441314203462 |
oct | 316771633722613 |
9 | 55323788777715 |
10 | 14224100140427 |
11 | 4594452787011 |
12 | 171888643514b |
13 | 7c2433231b38 |
14 | 3726431b59d9 |
15 | 19a005044b52 |
hex | cefce6fa58b |
14224100140427 has 2 divisors, whose sum is σ = 14224100140428. Its totient is φ = 14224100140426.
The previous prime is 14224100140399. The next prime is 14224100140451. The reversal of 14224100140427 is 72404100142241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14224100140427 - 212 = 14224100136331 is a prime.
It is a super-2 number, since 2×142241001404272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14224100140393 and 14224100140402.
It is not a weakly prime, because it can be changed into another prime (14224100143427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112050070213 + 7112050070214.
It is an arithmetic number, because the mean of its divisors is an integer number (7112050070214).
Almost surely, 214224100140427 is an apocalyptic number.
14224100140427 is a deficient number, since it is larger than the sum of its proper divisors (1).
14224100140427 is an equidigital number, since it uses as much as digits as its factorization.
14224100140427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14336, while the sum is 32.
Adding to 14224100140427 its reverse (72404100142241), we get a palindrome (86628200282668).
The spelling of 14224100140427 in words is "fourteen trillion, two hundred twenty-four billion, one hundred million, one hundred forty thousand, four hundred twenty-seven".
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