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1422412042333 is a prime number
BaseRepresentation
bin10100101100101110010…
…111010101000001011101
312000222111100012111202211
4110230232113111001131
5141301044440323313
63005240322320421
7204523460604232
oct24545627250135
95028440174684
101422412042333
114a9272574427
121ab80aab9111
13a4195c25799
144cbb8da7789
1527000a2ee3d
hex14b2e5d505d

1422412042333 has 2 divisors, whose sum is σ = 1422412042334. Its totient is φ = 1422412042332.

The previous prime is 1422412042327. The next prime is 1422412042411. The reversal of 1422412042333 is 3332402142241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1413371455609 + 9040586724 = 1188853^2 + 95082^2 .

It is a cyclic number.

It is not a de Polignac number, because 1422412042333 - 233 = 1413822107741 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1422412042295 and 1422412042304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1422412048333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711206021166 + 711206021167.

It is an arithmetic number, because the mean of its divisors is an integer number (711206021167).

Almost surely, 21422412042333 is an apocalyptic number.

It is an amenable number.

1422412042333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1422412042333 is an equidigital number, since it uses as much as digits as its factorization.

1422412042333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 1422412042333 its reverse (3332402142241), we get a palindrome (4754814184574).

The spelling of 1422412042333 in words is "one trillion, four hundred twenty-two billion, four hundred twelve million, forty-two thousand, three hundred thirty-three".