Base | Representation |
---|---|
bin | 1100111011111101000011… |
… | …1011101010011101110001 |
3 | 1212100210222220200020121012 |
4 | 3032333100323222131301 |
5 | 3331022020324042132 |
6 | 50130251452240305 |
7 | 2665442333152652 |
oct | 316772073523561 |
9 | 55323886606535 |
10 | 14224142018417 |
11 | 459447438a621 |
12 | 1718898470095 |
13 | 7c243bb05406 |
14 | 372648997529 |
15 | 19a008a680b2 |
hex | cefd0eea771 |
14224142018417 has 2 divisors, whose sum is σ = 14224142018418. Its totient is φ = 14224142018416.
The previous prime is 14224142018393. The next prime is 14224142018431. The reversal of 14224142018417 is 71481024142241.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12923730211681 + 1300411806736 = 3594959^2 + 1140356^2 .
It is a cyclic number.
It is not a de Polignac number, because 14224142018417 - 238 = 13949264111473 is a prime.
It is not a weakly prime, because it can be changed into another prime (14224142018467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112071009208 + 7112071009209.
It is an arithmetic number, because the mean of its divisors is an integer number (7112071009209).
Almost surely, 214224142018417 is an apocalyptic number.
It is an amenable number.
14224142018417 is a deficient number, since it is larger than the sum of its proper divisors (1).
14224142018417 is an equidigital number, since it uses as much as digits as its factorization.
14224142018417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 114688, while the sum is 41.
The spelling of 14224142018417 in words is "fourteen trillion, two hundred twenty-four billion, one hundred forty-two million, eighteen thousand, four hundred seventeen".
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