Base | Representation |
---|---|
bin | 1100111011111101010000… |
… | …0101101001100010000001 |
3 | 1212100211010121022100100001 |
4 | 3032333110011221202001 |
5 | 3331022122402431211 |
6 | 50130301023200001 |
7 | 2665443545212666 |
oct | 316772405514201 |
9 | 55324117270301 |
10 | 14224194967681 |
11 | 45944a1265146 |
12 | 17188b2146001 |
13 | 7c2449a8403a |
14 | 372651a1ba6d |
15 | 19a00d526ac1 |
hex | cefd4169881 |
14224194967681 has 2 divisors, whose sum is σ = 14224194967682. Its totient is φ = 14224194967680.
The previous prime is 14224194967579. The next prime is 14224194967769. The reversal of 14224194967681 is 18676949142241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13587775545600 + 636419422081 = 3686160^2 + 797759^2 .
It is a cyclic number.
It is not a de Polignac number, because 14224194967681 - 27 = 14224194967553 is a prime.
It is a super-2 number, since 2×142241949676812 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14224194967981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112097483840 + 7112097483841.
It is an arithmetic number, because the mean of its divisors is an integer number (7112097483841).
Almost surely, 214224194967681 is an apocalyptic number.
It is an amenable number.
14224194967681 is a deficient number, since it is larger than the sum of its proper divisors (1).
14224194967681 is an equidigital number, since it uses as much as digits as its factorization.
14224194967681 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 41803776, while the sum is 64.
The spelling of 14224194967681 in words is "fourteen trillion, two hundred twenty-four billion, one hundred ninety-four million, nine hundred sixty-seven thousand, six hundred eighty-one".
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