Base | Representation |
---|---|
bin | 1100111011111110001011… |
… | …1100110001111101001011 |
3 | 1212100211202222110210112021 |
4 | 3032333202330301331023 |
5 | 3331023130220114011 |
6 | 50130341451225311 |
7 | 2665452663420451 |
oct | 316774274617513 |
9 | 55324688423467 |
10 | 14224444301131 |
11 | 4594609a83049 |
12 | 1718961748237 |
13 | 7c248962221c |
14 | 372676ba29d1 |
15 | 19a025378471 |
hex | cefe2f31f4b |
14224444301131 has 2 divisors, whose sum is σ = 14224444301132. Its totient is φ = 14224444301130.
The previous prime is 14224444301069. The next prime is 14224444301149. The reversal of 14224444301131 is 13110344442241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14224444301131 - 219 = 14224443776843 is a prime.
It is a super-2 number, since 2×142244443011312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14224444301231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112222150565 + 7112222150566.
It is an arithmetic number, because the mean of its divisors is an integer number (7112222150566).
Almost surely, 214224444301131 is an apocalyptic number.
14224444301131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14224444301131 is an equidigital number, since it uses as much as digits as its factorization.
14224444301131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36864, while the sum is 34.
Adding to 14224444301131 its reverse (13110344442241), we get a palindrome (27334788743372).
The spelling of 14224444301131 in words is "fourteen trillion, two hundred twenty-four billion, four hundred forty-four million, three hundred one thousand, one hundred thirty-one".
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