Search a number
-
+
1422645533 is a prime number
BaseRepresentation
bin101010011001011…
…1101100100011101
310200010221212210022
41110302331210131
510403144124113
6353100121525
750153200421
oct12462754435
93603855708
101422645533
11670056711
123385362a5
1319897a0ba
14d6d28b81
1584d69908
hex54cbd91d

1422645533 has 2 divisors, whose sum is σ = 1422645534. Its totient is φ = 1422645532.

The previous prime is 1422645503. The next prime is 1422645541. The reversal of 1422645533 is 3355462241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1321904164 + 100741369 = 36358^2 + 10037^2 .

It is an emirp because it is prime and its reverse (3355462241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1422645533 - 214 = 1422629149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1422645493 and 1422645502.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1422645503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711322766 + 711322767.

It is an arithmetic number, because the mean of its divisors is an integer number (711322767).

Almost surely, 21422645533 is an apocalyptic number.

It is an amenable number.

1422645533 is a deficient number, since it is larger than the sum of its proper divisors (1).

1422645533 is an equidigital number, since it uses as much as digits as its factorization.

1422645533 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 86400, while the sum is 35.

The square root of 1422645533 is about 37717.9736067568. The cubic root of 1422645533 is about 1124.6884491693.

The spelling of 1422645533 in words is "one billion, four hundred twenty-two million, six hundred forty-five thousand, five hundred thirty-three".