Base | Representation |
---|---|
bin | 11010011111111011… |
… | …01000111100110111 |
3 | 1100201110121001221101 |
4 | 31033331220330313 |
5 | 213113433213341 |
6 | 10311402230531 |
7 | 1012354630066 |
oct | 151775507467 |
9 | 40643531841 |
10 | 14226460471 |
11 | 6040514353 |
12 | 29104b5447 |
13 | 14594cc062 |
14 | 98d5c61dd |
15 | 583e67831 |
hex | 34ff68f37 |
14226460471 has 2 divisors, whose sum is σ = 14226460472. Its totient is φ = 14226460470.
The previous prime is 14226460439. The next prime is 14226460561. The reversal of 14226460471 is 17406462241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14226460471 - 25 = 14226460439 is a prime.
It is a super-3 number, since 3×142264604713 (a number of 31 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14226460471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14226461471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7113230235 + 7113230236.
It is an arithmetic number, because the mean of its divisors is an integer number (7113230236).
Almost surely, 214226460471 is an apocalyptic number.
14226460471 is a deficient number, since it is larger than the sum of its proper divisors (1).
14226460471 is an equidigital number, since it uses as much as digits as its factorization.
14226460471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 37.
The spelling of 14226460471 in words is "fourteen billion, two hundred twenty-six million, four hundred sixty thousand, four hundred seventy-one".
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