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1423000144551 = 39725719027373
BaseRepresentation
bin10100101101010001011…
…010110000101010100111
312001001000022211012100110
4110231101122300222213
5141303301014111201
63005414531344103
7204544161441036
oct24552132605247
95031008735313
101423000144551
114a9544536317
121ab953a52033
13a425aa16a6b
144cc3313471d
152703749c6d6
hex14b516b0aa7

1423000144551 has 16 divisors (see below), whose sum is σ = 1924352496864. Its totient is φ = 935233388544.

The previous prime is 1423000144549. The next prime is 1423000144561. The reversal of 1423000144551 is 1554410003241.

It is not a de Polignac number, because 1423000144551 - 21 = 1423000144549 is a prime.

It is a super-2 number, since 2×14230001445512 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1423000144561) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9438900 + ... + 9588473.

It is an arithmetic number, because the mean of its divisors is an integer number (120272031054).

Almost surely, 21423000144551 is an apocalyptic number.

1423000144551 is a deficient number, since it is larger than the sum of its proper divisors (501352352313).

1423000144551 is a wasteful number, since it uses less digits than its factorization.

1423000144551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19027730.

The product of its (nonzero) digits is 9600, while the sum is 30.

Adding to 1423000144551 its reverse (1554410003241), we get a palindrome (2977410147792).

The spelling of 1423000144551 in words is "one trillion, four hundred twenty-three billion, one hundred forty-four thousand, five hundred fifty-one".

Divisors: 1 3 97 257 291 771 24929 74787 19027373 57082119 1845655181 4890034861 5536965543 14670104583 474333381517 1423000144551