14230042112333 has 2 divisors, whose sum is σ = 14230042112334. Its totient is φ = 14230042112332.

The previous prime is 14230042112261. The next prime is 14230042112369. The reversal of 14230042112333 is 33321124003241.

14230042112333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7908226992649 + 6321815119684 = 2812157^2 + 2514322^2 .

It is an emirp because it is prime and its reverse (33321124003241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14230042112333 - 2⁴⁰ = 13130530484557 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14230042112296 and 14230042112305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14230042118333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115021056166 + 7115021056167.

It is an arithmetic number, because the mean of its divisors is an integer number (7115021056167).

Almost surely, 2^{14230042112333} is an apocalyptic number.

It is an amenable number.

14230042112333 is a deficient number, since it is larger than the sum of its proper divisors (1).

14230042112333 is an equidigital number, since it uses as much as digits as its factorization.

14230042112333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 14230042112333 its reverse (33321124003241), we get a palindrome (47551166115574).

The spelling of 14230042112333 in words is "fourteen trillion, two hundred thirty billion, forty-two million, one hundred twelve thousand, three hundred thirty-three".