Base | Representation |
---|---|
bin | 1100111100010100111001… |
… | …0010001001101000001011 |
3 | 1212101102111210200000222121 |
4 | 3033011032102021220023 |
5 | 3331123121222020043 |
6 | 50133230404032111 |
7 | 2666060022322213 |
oct | 317051622115013 |
9 | 55342453600877 |
10 | 14230540032523 |
11 | 459715794a291 |
12 | 1719b83092637 |
13 | 7c2c1b498889 |
14 | 372a945b1243 |
15 | 19a2805c0ded |
hex | cf14e489a0b |
14230540032523 has 2 divisors, whose sum is σ = 14230540032524. Its totient is φ = 14230540032522.
The previous prime is 14230540032503. The next prime is 14230540032571. The reversal of 14230540032523 is 32523004503241.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14230540032523 is a prime.
It is not a weakly prime, because it can be changed into another prime (14230540032503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115270016261 + 7115270016262.
It is an arithmetic number, because the mean of its divisors is an integer number (7115270016262).
Almost surely, 214230540032523 is an apocalyptic number.
14230540032523 is a deficient number, since it is larger than the sum of its proper divisors (1).
14230540032523 is an equidigital number, since it uses as much as digits as its factorization.
14230540032523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 34.
Adding to 14230540032523 its reverse (32523004503241), we get a palindrome (46753544535764).
The spelling of 14230540032523 in words is "fourteen trillion, two hundred thirty billion, five hundred forty million, thirty-two thousand, five hundred twenty-three".
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