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142305806897 is a prime number
BaseRepresentation
bin1000010010001000010…
…1100100101000110001
3111121022112111000011122
42010202011210220301
54312420241310042
6145212511152025
713165320254252
oct2044205445061
9447275430148
10142305806897
1155395a10a81
12236b5b15615
131055b4bb287
146c5d96cb29
153a7d38d7d2
hex2122164a31

142305806897 has 2 divisors, whose sum is σ = 142305806898. Its totient is φ = 142305806896.

The previous prime is 142305806873. The next prime is 142305806927. The reversal of 142305806897 is 798608503241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114363006976 + 27942799921 = 338176^2 + 167161^2 .

It is a cyclic number.

It is not a de Polignac number, because 142305806897 - 212 = 142305802801 is a prime.

It is not a weakly prime, because it can be changed into another prime (142305806827) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71152903448 + 71152903449.

It is an arithmetic number, because the mean of its divisors is an integer number (71152903449).

It is a 1-persistent number, because it is pandigital, but 2⋅142305806897 = 284611613794 is not.

Almost surely, 2142305806897 is an apocalyptic number.

It is an amenable number.

142305806897 is a deficient number, since it is larger than the sum of its proper divisors (1).

142305806897 is an equidigital number, since it uses as much as digits as its factorization.

142305806897 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2903040, while the sum is 53.

The spelling of 142305806897 in words is "one hundred forty-two billion, three hundred five million, eight hundred six thousand, eight hundred ninety-seven".