Base | Representation |
---|---|
bin | 1100111100010111101111… |
… | …0100100011000101010111 |
3 | 1212101111111001020211211022 |
4 | 3033011323310203011113 |
5 | 3331131202312240112 |
6 | 50133434255031355 |
7 | 2666114660204621 |
oct | 317057364430527 |
9 | 55344431224738 |
10 | 14231304024407 |
11 | 459750a126738 |
12 | 171a156b0b55b |
13 | 7c3010851b92 |
14 | 372b27c45c11 |
15 | 19a2c76d3d72 |
hex | cf17bd23157 |
14231304024407 has 2 divisors, whose sum is σ = 14231304024408. Its totient is φ = 14231304024406.
The previous prime is 14231304024367. The next prime is 14231304024473. The reversal of 14231304024407 is 70442040313241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14231304024407 - 210 = 14231304023383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14231304014407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115652012203 + 7115652012204.
It is an arithmetic number, because the mean of its divisors is an integer number (7115652012204).
Almost surely, 214231304024407 is an apocalyptic number.
14231304024407 is a deficient number, since it is larger than the sum of its proper divisors (1).
14231304024407 is an equidigital number, since it uses as much as digits as its factorization.
14231304024407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 14231304024407 its reverse (70442040313241), we get a palindrome (84673344337648).
The spelling of 14231304024407 in words is "fourteen trillion, two hundred thirty-one billion, three hundred four million, twenty-four thousand, four hundred seven".
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