Base | Representation |
---|---|
bin | 10100101101011001010… |
… | …111001100001100001011 |
3 | 12001001100121121121201211 |
4 | 110231121113030030023 |
5 | 141304034124121233 |
6 | 3005440052153551 |
7 | 204550400351011 |
oct | 24553127141413 |
9 | 5031317547654 |
10 | 1423133426443 |
11 | 4a9602799a43 |
12 | 1ab9906088b7 |
13 | a427c5112a1 |
14 | 4cc46b0a8b1 |
15 | 270440285cd |
hex | 14b595cc30b |
1423133426443 has 2 divisors, whose sum is σ = 1423133426444. Its totient is φ = 1423133426442.
The previous prime is 1423133426437. The next prime is 1423133426483. The reversal of 1423133426443 is 3446243313241.
It is an a-pointer prime, because the next prime (1423133426483) can be obtained adding 1423133426443 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1423133426443 - 237 = 1285694472971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1423133426396 and 1423133426405.
It is not a weakly prime, because it can be changed into another prime (1423133426413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711566713221 + 711566713222.
It is an arithmetic number, because the mean of its divisors is an integer number (711566713222).
Almost surely, 21423133426443 is an apocalyptic number.
1423133426443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1423133426443 is an equidigital number, since it uses as much as digits as its factorization.
1423133426443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 497664, while the sum is 40.
Adding to 1423133426443 its reverse (3446243313241), we get a palindrome (4869376739684).
The spelling of 1423133426443 in words is "one trillion, four hundred twenty-three billion, one hundred thirty-three million, four hundred twenty-six thousand, four hundred forty-three".
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