Base | Representation |
---|---|
bin | 100000010110111101001100… |
… | …111101000001000101011011 |
3 | 200122220011222022011022012212 |
4 | 200112331030331001011123 |
5 | 122123142141244312403 |
6 | 1222402342350025335 |
7 | 41655631113121124 |
oct | 4026751475010533 |
9 | 618804868138185 |
10 | 142315032416603 |
11 | 41389514721422 |
12 | 13b657344a824b |
13 | 615433325c627 |
14 | 272012754104b |
15 | 116be197424d8 |
hex | 816f4cf4115b |
142315032416603 has 2 divisors, whose sum is σ = 142315032416604. Its totient is φ = 142315032416602.
The previous prime is 142315032416591. The next prime is 142315032416611. The reversal of 142315032416603 is 306614230513241.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142315032416603 - 216 = 142315032351067 is a prime.
It is not a weakly prime, because it can be changed into another prime (142315032416663) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71157516208301 + 71157516208302.
It is an arithmetic number, because the mean of its divisors is an integer number (71157516208302).
Almost surely, 2142315032416603 is an apocalyptic number.
142315032416603 is a deficient number, since it is larger than the sum of its proper divisors (1).
142315032416603 is an equidigital number, since it uses as much as digits as its factorization.
142315032416603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 41.
Adding to 142315032416603 its reverse (306614230513241), we get a palindrome (448929262929844).
The spelling of 142315032416603 in words is "one hundred forty-two trillion, three hundred fifteen billion, thirty-two million, four hundred sixteen thousand, six hundred three".
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