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142320995625043 is a prime number
BaseRepresentation
bin100000010111000010110000…
…011000110110100001010011
3200122220202100212222200100201
4200113002300120312201103
5122123241344340000133
61222405210210200031
741656231642423354
oct4027026030664123
9618822325880321
10142320995625043
1141390aa4803164
1213b66919583017
136154a73816031
1427205314d3d2b
15116c16800dd7d
hex8170b0636853

142320995625043 has 2 divisors, whose sum is σ = 142320995625044. Its totient is φ = 142320995625042.

The previous prime is 142320995625041. The next prime is 142320995625079. The reversal of 142320995625043 is 340526599023241.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 142320995625043 - 21 = 142320995625041 is a prime.

Together with 142320995625041, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (142320995625041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71160497812521 + 71160497812522.

It is an arithmetic number, because the mean of its divisors is an integer number (71160497812522).

Almost surely, 2142320995625043 is an apocalyptic number.

142320995625043 is a deficient number, since it is larger than the sum of its proper divisors (1).

142320995625043 is an equidigital number, since it uses as much as digits as its factorization.

142320995625043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13996800, while the sum is 55.

The spelling of 142320995625043 in words is "one hundred forty-two trillion, three hundred twenty billion, nine hundred ninety-five million, six hundred twenty-five thousand, forty-three".