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142321024112557 is a prime number
BaseRepresentation
bin100000010111000010110010…
…000101100001011110101101
3200122220202102212120222212211
4200113002302011201132231
5122123241424133100212
61222405213104530421
741656232436522343
oct4027026205413655
9618822385528784
10142321024112557
11413910098a0264
1213b66927020a11
136154a796ab754
1427205351cb993
15116c16a7899a7
hex8170b21617ad

142321024112557 has 2 divisors, whose sum is σ = 142321024112558. Its totient is φ = 142321024112556.

The previous prime is 142321024112543. The next prime is 142321024112633. The reversal of 142321024112557 is 755211420123241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 79084986564676 + 63236037547881 = 8892974^2 + 7952109^2 .

It is a cyclic number.

It is not a de Polignac number, because 142321024112557 - 215 = 142321024079789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142321024212557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71160512056278 + 71160512056279.

It is an arithmetic number, because the mean of its divisors is an integer number (71160512056279).

Almost surely, 2142321024112557 is an apocalyptic number.

It is an amenable number.

142321024112557 is a deficient number, since it is larger than the sum of its proper divisors (1).

142321024112557 is an equidigital number, since it uses as much as digits as its factorization.

142321024112557 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 134400, while the sum is 40.

Adding to 142321024112557 its reverse (755211420123241), we get a palindrome (897532444235798).

The spelling of 142321024112557 in words is "one hundred forty-two trillion, three hundred twenty-one billion, twenty-four million, one hundred twelve thousand, five hundred fifty-seven".