Base | Representation |
---|---|
bin | 100000010111000111011011… |
… | …011110101011111011101111 |
3 | 200122221020022121002021112121 |
4 | 200113013123132223323233 |
5 | 122123332133431322002 |
6 | 1222411400141413411 |
7 | 41656500203133262 |
oct | 4027073336537357 |
9 | 618836277067477 |
10 | 142326013542127 |
11 | 4139313a238578 |
12 | 13b67899b6a267 |
13 | 61553932a8c3c |
14 | 2720889adacd9 |
15 | 116c35d804237 |
hex | 8171db7abeef |
142326013542127 has 2 divisors, whose sum is σ = 142326013542128. Its totient is φ = 142326013542126.
The previous prime is 142326013542121. The next prime is 142326013542137. The reversal of 142326013542127 is 721245310623241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 142326013542127 - 211 = 142326013540079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142326013542121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71163006771063 + 71163006771064.
It is an arithmetic number, because the mean of its divisors is an integer number (71163006771064).
Almost surely, 2142326013542127 is an apocalyptic number.
142326013542127 is a deficient number, since it is larger than the sum of its proper divisors (1).
142326013542127 is an equidigital number, since it uses as much as digits as its factorization.
142326013542127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 483840, while the sum is 43.
The spelling of 142326013542127 in words is "one hundred forty-two trillion, three hundred twenty-six billion, thirteen million, five hundred forty-two thousand, one hundred twenty-seven".
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