Base | Representation |
---|---|
bin | 10100101101100011011… |
… | …000011110001100011001 |
3 | 12001001210022221101121202 |
4 | 110231203120132030121 |
5 | 141304410143100424 |
6 | 3005504455243545 |
7 | 204554511266642 |
oct | 24554330361431 |
9 | 5031708841552 |
10 | 1423301534489 |
11 | 4a968967a00a |
12 | 1aba189795b5 |
13 | a42a82b03c3 |
14 | 4cc6118a6c9 |
15 | 27053b832ae |
hex | 14b6361e319 |
1423301534489 has 2 divisors, whose sum is σ = 1423301534490. Its totient is φ = 1423301534488.
The previous prime is 1423301534467. The next prime is 1423301534561. The reversal of 1423301534489 is 9844351033241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1418976499264 + 4325035225 = 1191208^2 + 65765^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1423301534489 is a prime.
It is a super-2 number, since 2×14233015344892 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1423301594489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711650767244 + 711650767245.
It is an arithmetic number, because the mean of its divisors is an integer number (711650767245).
Almost surely, 21423301534489 is an apocalyptic number.
It is an amenable number.
1423301534489 is a deficient number, since it is larger than the sum of its proper divisors (1).
1423301534489 is an equidigital number, since it uses as much as digits as its factorization.
1423301534489 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160, while the sum is 47.
The spelling of 1423301534489 in words is "one trillion, four hundred twenty-three billion, three hundred one million, five hundred thirty-four thousand, four hundred eighty-nine".
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