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1423312353137 is a prime number
BaseRepresentation
bin10100101101100100000…
…001101111011101110001
312001001211002022001000102
4110231210001233131301
5141304420430300022
63005505523202145
7204555002246123
oct24554401573561
95031732261012
101423312353137
114a9694799244
121aba20516355
13a42aa5ca77c
144cc627a5213
1527054abda92
hex14b6406f771

1423312353137 has 2 divisors, whose sum is σ = 1423312353138. Its totient is φ = 1423312353136.

The previous prime is 1423312353097. The next prime is 1423312353149. The reversal of 1423312353137 is 7313532133241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1423048583056 + 263770081 = 1192916^2 + 16241^2 .

It is a cyclic number.

It is not a de Polignac number, because 1423312353137 - 214 = 1423312336753 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1423312353137.

It is not a weakly prime, because it can be changed into another prime (1423312323137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711656176568 + 711656176569.

It is an arithmetic number, because the mean of its divisors is an integer number (711656176569).

Almost surely, 21423312353137 is an apocalyptic number.

It is an amenable number.

1423312353137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1423312353137 is an equidigital number, since it uses as much as digits as its factorization.

1423312353137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 136080, while the sum is 38.

Adding to 1423312353137 its reverse (7313532133241), we get a palindrome (8736844486378).

The spelling of 1423312353137 in words is "one trillion, four hundred twenty-three billion, three hundred twelve million, three hundred fifty-three thousand, one hundred thirty-seven".