Base | Representation |
---|---|
bin | 1100111100011111001101… |
… | …1001001010110111000111 |
3 | 1212101200122212001201100002 |
4 | 3033013303121022313013 |
5 | 3331144304342110343 |
6 | 50134405320311515 |
7 | 2666215456526225 |
oct | 317076331126707 |
9 | 55350585051302 |
10 | 14233310113223 |
11 | 4598349551983 |
12 | 171a61691259b |
13 | 7c327034b796 |
14 | 372c78447b15 |
15 | 19a39389a8b8 |
hex | cf1f364adc7 |
14233310113223 has 2 divisors, whose sum is σ = 14233310113224. Its totient is φ = 14233310113222.
The previous prime is 14233310113199. The next prime is 14233310113277. The reversal of 14233310113223 is 32231101333241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14233310113223 - 214 = 14233310096839 is a prime.
It is a super-2 number, since 2×142333101132232 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14233310113723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7116655056611 + 7116655056612.
It is an arithmetic number, because the mean of its divisors is an integer number (7116655056612).
Almost surely, 214233310113223 is an apocalyptic number.
14233310113223 is a deficient number, since it is larger than the sum of its proper divisors (1).
14233310113223 is an equidigital number, since it uses as much as digits as its factorization.
14233310113223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 14233310113223 its reverse (32231101333241), we get a palindrome (46464411446464).
The spelling of 14233310113223 in words is "fourteen trillion, two hundred thirty-three billion, three hundred ten million, one hundred thirteen thousand, two hundred twenty-three".
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