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1423340006503 is a prime number
BaseRepresentation
bin10100101101100101101…
…011001110110001100111
312001001220000022222022011
4110231211223032301213
5141310000020202003
63005512352015051
7204555456302152
oct24554553166147
95031800288264
101423340006503
114a96a9366668
121aba29831487
13a42b32605cc
144cc66322c99
152705723246d
hex14b65acec67

1423340006503 has 2 divisors, whose sum is σ = 1423340006504. Its totient is φ = 1423340006502.

The previous prime is 1423340006441. The next prime is 1423340006509. The reversal of 1423340006503 is 3056000433241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1423340006503 is a prime.

It is a super-2 number, since 2×14233400065032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1423340006509) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711670003251 + 711670003252.

It is an arithmetic number, because the mean of its divisors is an integer number (711670003252).

Almost surely, 21423340006503 is an apocalyptic number.

1423340006503 is a deficient number, since it is larger than the sum of its proper divisors (1).

1423340006503 is an equidigital number, since it uses as much as digits as its factorization.

1423340006503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 1423340006503 its reverse (3056000433241), we get a palindrome (4479340439744).

The spelling of 1423340006503 in words is "one trillion, four hundred twenty-three billion, three hundred forty million, six thousand, five hundred three".