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1423400241313 is a prime number
BaseRepresentation
bin10100101101101001010…
…001000000100010100001
312001002001012200012221001
4110231221101000202201
5141310110430210223
63005522343032001
7204560120264641
oct24555121004241
95032035605831
101423400241313
114a972a3679a6
121aba45a3b601
13a42c28903cb
144cc70322521
152705c67e9ad
hex14b694408a1

1423400241313 has 2 divisors, whose sum is σ = 1423400241314. Its totient is φ = 1423400241312.

The previous prime is 1423400241283. The next prime is 1423400241323. The reversal of 1423400241313 is 3131420043241.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1368871920144 + 54528321169 = 1169988^2 + 233513^2 .

It is a cyclic number.

It is not a de Polignac number, because 1423400241313 - 25 = 1423400241281 is a prime.

It is not a weakly prime, because it can be changed into another prime (1423400241323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711700120656 + 711700120657.

It is an arithmetic number, because the mean of its divisors is an integer number (711700120657).

Almost surely, 21423400241313 is an apocalyptic number.

It is an amenable number.

1423400241313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1423400241313 is an equidigital number, since it uses as much as digits as its factorization.

1423400241313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1423400241313 its reverse (3131420043241), we get a palindrome (4554820284554).

The spelling of 1423400241313 in words is "one trillion, four hundred twenty-three billion, four hundred million, two hundred forty-one thousand, three hundred thirteen".