Base | Representation |
---|---|
bin | 1100111100100001110100… |
… | …1011101001110110100001 |
3 | 1212101202110201022021201112 |
4 | 3033020131023221312201 |
5 | 3331202223332310332 |
6 | 50135003043313105 |
7 | 2666242032011435 |
oct | 317103513516641 |
9 | 55352421267645 |
10 | 14234011213217 |
11 | 4598679282764 |
12 | 171a79167b795 |
13 | 7c3352684753 |
14 | 372d035ca9c5 |
15 | 19a3d51d8db2 |
hex | cf21d2e9da1 |
14234011213217 has 2 divisors, whose sum is σ = 14234011213218. Its totient is φ = 14234011213216.
The previous prime is 14234011213189. The next prime is 14234011213337. The reversal of 14234011213217 is 71231211043241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7593860444416 + 6640150768801 = 2755696^2 + 2576849^2 .
It is a cyclic number.
It is not a de Polignac number, because 14234011213217 - 210 = 14234011212193 is a prime.
It is not a weakly prime, because it can be changed into another prime (14234011513217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7117005606608 + 7117005606609.
It is an arithmetic number, because the mean of its divisors is an integer number (7117005606609).
Almost surely, 214234011213217 is an apocalyptic number.
It is an amenable number.
14234011213217 is a deficient number, since it is larger than the sum of its proper divisors (1).
14234011213217 is an equidigital number, since it uses as much as digits as its factorization.
14234011213217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 14234011213217 its reverse (71231211043241), we get a palindrome (85465222256458).
The spelling of 14234011213217 in words is "fourteen trillion, two hundred thirty-four billion, eleven million, two hundred thirteen thousand, two hundred seventeen".
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