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14234032410307 is a prime number
BaseRepresentation
bin1100111100100001111001…
…1100100000111011000011
31212101202112012012012122221
43033020132130200323003
53331202244244112212
650135005121511511
72666242410124513
oct317103634407303
955352465165587
1014234032410307
11459868a240416
12171a7987a2597
137c3356b969c8
14372d06347843
1519a3d6ec4807
hexcf21e720ec3

14234032410307 has 2 divisors, whose sum is σ = 14234032410308. Its totient is φ = 14234032410306.

The previous prime is 14234032410293. The next prime is 14234032410413. The reversal of 14234032410307 is 70301423043241.

14234032410307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14234032410307 - 243 = 5437939388099 is a prime.

It is not a weakly prime, because it can be changed into another prime (14234035410307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7117016205153 + 7117016205154.

It is an arithmetic number, because the mean of its divisors is an integer number (7117016205154).

Almost surely, 214234032410307 is an apocalyptic number.

14234032410307 is a deficient number, since it is larger than the sum of its proper divisors (1).

14234032410307 is an equidigital number, since it uses as much as digits as its factorization.

14234032410307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 34.

Adding to 14234032410307 its reverse (70301423043241), we get a palindrome (84535455453548).

The spelling of 14234032410307 in words is "fourteen trillion, two hundred thirty-four billion, thirty-two million, four hundred ten thousand, three hundred seven".