142341231412433 has 2 divisors, whose sum is σ = 142341231412434. Its totient is φ = 142341231412432.

The previous prime is 142341231412409. The next prime is 142341231412447. The reversal of 142341231412433 is 334214132143241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90550582861249 + 51790648551184 = 9515807^2 + 7196572^2 .

It is a cyclic number.

It is not a de Polignac number, because 142341231412433 - 2¹⁰ = 142341231411409 is a prime.

It is a super-2 number, since 2×142341231412433² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (142341231412453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71170615706216 + 71170615706217.

It is an arithmetic number, because the mean of its divisors is an integer number (71170615706217).

Almost surely, 2^{142341231412433} is an apocalyptic number.

It is an amenable number.

142341231412433 is a deficient number, since it is larger than the sum of its proper divisors (1).

142341231412433 is an equidigital number, since it uses as much as digits as its factorization.

142341231412433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 165888, while the sum is 38.

Adding to 142341231412433 its reverse (334214132143241), we get a palindrome (476555363555674).

The spelling of 142341231412433 in words is "one hundred forty-two trillion, three hundred forty-one billion, two hundred thirty-one million, four hundred twelve thousand, four hundred thirty-three".