14234131 has 2 divisors, whose sum is σ = 14234132. Its totient is φ = 14234130.

The previous prime is 14234113. The next prime is 14234137. The reversal of 14234131 is 13143241.

14234131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (14234113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (13143241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14234131 - 2¹⁷ = 14103059 is a prime.

It is a super-2 number, since 2×14234131² = 405220970650322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14234099 and 14234108.

It is not a weakly prime, because it can be changed into another prime (14234137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7117065 + 7117066.

It is an arithmetic number, because the mean of its divisors is an integer number (7117066).

Almost surely, 2^14234131 is an apocalyptic number.

14234131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14234131 is an equidigital number, since it uses as much as digits as its factorization.

14234131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 288, while the sum is 19.

The square root of 14234131 is about 3772.8147317354. The cubic root of 14234131 is about 242.3503508617.

Adding to 14234131 its reverse (13143241), we get a palindrome (27377372).

It can be divided in two parts, 14234 and 131, that added together give a triangular number (14365 = T₁₆₉).

The spelling of 14234131 in words is "fourteen million, two hundred thirty-four thousand, one hundred thirty-one".