Base | Representation |
---|---|
bin | 1100111100100010010001… |
… | …1001010110011011101011 |
3 | 1212101202210011001022000122 |
4 | 3033020210121112123223 |
5 | 3331203000323303303 |
6 | 50135023045353455 |
7 | 2666245031525444 |
oct | 317104431263353 |
9 | 55352704038018 |
10 | 14234132244203 |
11 | 4598730629073 |
12 | 171a80610888b |
13 | 7c337177ca11 |
14 | 372d156d42cb |
15 | 19a3e0b44e38 |
hex | cf2246566eb |
14234132244203 has 2 divisors, whose sum is σ = 14234132244204. Its totient is φ = 14234132244202.
The previous prime is 14234132244197. The next prime is 14234132244323. The reversal of 14234132244203 is 30244223143241.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14234132244203 - 216 = 14234132178667 is a prime.
It is a super-2 number, since 2×142341322442032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14234132240203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7117066122101 + 7117066122102.
It is an arithmetic number, because the mean of its divisors is an integer number (7117066122102).
Almost surely, 214234132244203 is an apocalyptic number.
14234132244203 is a deficient number, since it is larger than the sum of its proper divisors (1).
14234132244203 is an equidigital number, since it uses as much as digits as its factorization.
14234132244203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 14234132244203 its reverse (30244223143241), we get a palindrome (44478355387444).
The spelling of 14234132244203 in words is "fourteen trillion, two hundred thirty-four billion, one hundred thirty-two million, two hundred forty-four thousand, two hundred three".
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