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14234147233 is a prime number
BaseRepresentation
bin11010100000110101…
…11101100110100001
31100202000001121012021
431100122331212201
5213122420202413
610312235101441
71012510153345
oct152032754641
940660047167
1014234147233
116044894549
122912ba1881
13145ac90a37
14990627625
1558498518d
hex3506bd9a1

14234147233 has 2 divisors, whose sum is σ = 14234147234. Its totient is φ = 14234147232.

The previous prime is 14234147203. The next prime is 14234147261. The reversal of 14234147233 is 33274143241.

14234147233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12641179489 + 1592967744 = 112433^2 + 39912^2 .

It is an emirp because it is prime and its reverse (33274143241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14234147233 - 217 = 14234016161 is a prime.

It is a super-2 number, since 2×142341472332 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14234147203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7117073616 + 7117073617.

It is an arithmetic number, because the mean of its divisors is an integer number (7117073617).

Almost surely, 214234147233 is an apocalyptic number.

It is an amenable number.

14234147233 is a deficient number, since it is larger than the sum of its proper divisors (1).

14234147233 is an equidigital number, since it uses as much as digits as its factorization.

14234147233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48384, while the sum is 34.

The spelling of 14234147233 in words is "fourteen billion, two hundred thirty-four million, one hundred forty-seven thousand, two hundred thirty-three".