142341500657 has 2 divisors, whose sum is σ = 142341500658. Its totient is φ = 142341500656.

The previous prime is 142341500629. The next prime is 142341500687. The reversal of 142341500657 is 756005143241.

142341500657 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132204232801 + 10137267856 = 363599^2 + 100684^2 .

It is an emirp because it is prime and its reverse (756005143241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142341500657 is a prime.

It is a super-3 number, since 3×142341500657³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 142341500657.

It is not a weakly prime, because it can be changed into another prime (142341500687) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71170750328 + 71170750329.

It is an arithmetic number, because the mean of its divisors is an integer number (71170750329).

Almost surely, 2^142341500657 is an apocalyptic number.

It is an amenable number.

142341500657 is a deficient number, since it is larger than the sum of its proper divisors (1).

142341500657 is an equidigital number, since it uses as much as digits as its factorization.

142341500657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100800, while the sum is 38.

Adding to 142341500657 its reverse (756005143241), we get a palindrome (898346643898).

The spelling of 142341500657 in words is "one hundred forty-two billion, three hundred forty-one million, five hundred thousand, six hundred fifty-seven".