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142355232343477 is a prime number
BaseRepresentation
bin100000010111100010101001…
…000011100100010110110101
3200200001000201220102011211101
4200113202221003210112311
5122124322003434442402
61222433031350010101
741661553235633116
oct4027425103442665
9620030656364741
10142355232343477
11413a457351248a
1213b71493346931
13615806b871aca
14272205c4b220d
15116cebda6bb87
hex8178a90e45b5

142355232343477 has 2 divisors, whose sum is σ = 142355232343478. Its totient is φ = 142355232343476.

The previous prime is 142355232343397. The next prime is 142355232343549. The reversal of 142355232343477 is 774343232553241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 137366861970321 + 4988370373156 = 11720361^2 + 2233466^2 .

It is a cyclic number.

It is not a de Polignac number, because 142355232343477 - 211 = 142355232341429 is a prime.

It is a super-2 number, since 2×1423552323434772 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142355232344477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71177616171738 + 71177616171739.

It is an arithmetic number, because the mean of its divisors is an integer number (71177616171739).

Almost surely, 2142355232343477 is an apocalyptic number.

It is an amenable number.

142355232343477 is a deficient number, since it is larger than the sum of its proper divisors (1).

142355232343477 is an equidigital number, since it uses as much as digits as its factorization.

142355232343477 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 50803200, while the sum is 55.

The spelling of 142355232343477 in words is "one hundred forty-two trillion, three hundred fifty-five billion, two hundred thirty-two million, three hundred forty-three thousand, four hundred seventy-seven".