Base | Representation |
---|---|
bin | 100000010111100111010001… |
… | …001010111101010001101011 |
3 | 200200001111120010120101001122 |
4 | 200113213101022331101223 |
5 | 122124412142241231431 |
6 | 1222435212335205455 |
7 | 41662120322112554 |
oct | 4027472112752153 |
9 | 620044503511048 |
10 | 142360200336491 |
11 | 413a6692849135 |
12 | 13b7243b07688b |
13 | 6158680ba5047 |
14 | 27223b020132b |
15 | 116d1aec9ea7b |
hex | 8179d12bd46b |
142360200336491 has 2 divisors, whose sum is σ = 142360200336492. Its totient is φ = 142360200336490.
The previous prime is 142360200336467. The next prime is 142360200336493. The reversal of 142360200336491 is 194633002063241.
142360200336491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142360200336491 is a prime.
Together with 142360200336493, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (142360200336493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71180100168245 + 71180100168246.
It is an arithmetic number, because the mean of its divisors is an integer number (71180100168246).
Almost surely, 2142360200336491 is an apocalyptic number.
142360200336491 is a deficient number, since it is larger than the sum of its proper divisors (1).
142360200336491 is an equidigital number, since it uses as much as digits as its factorization.
142360200336491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 44.
The spelling of 142360200336491 in words is "one hundred forty-two trillion, three hundred sixty billion, two hundred million, three hundred thirty-six thousand, four hundred ninety-one".
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