Base | Representation |
---|---|
bin | 100000010111101100010110… |
… | …110110000100010000110001 |
3 | 200200002000122220212001022101 |
4 | 200113230112312010100301 |
5 | 122130004340020414442 |
6 | 1222441514441340401 |
7 | 41662402606343536 |
oct | 4027542666042061 |
9 | 620060586761271 |
10 | 142365664232497 |
11 | 413a8a36aa3072 |
12 | 13b73504a97701 |
13 | 6159041b875c4 |
14 | 272276bb3ad8d |
15 | 116d3ce7dbcb7 |
hex | 817b16d84431 |
142365664232497 has 2 divisors, whose sum is σ = 142365664232498. Its totient is φ = 142365664232496.
The previous prime is 142365664232419. The next prime is 142365664232503. The reversal of 142365664232497 is 794232466563241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101584144578816 + 40781519653681 = 10078896^2 + 6386041^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142365664232497 is a prime.
It is not a weakly prime, because it can be changed into another prime (142365664332497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71182832116248 + 71182832116249.
It is an arithmetic number, because the mean of its divisors is an integer number (71182832116249).
Almost surely, 2142365664232497 is an apocalyptic number.
It is an amenable number.
142365664232497 is a deficient number, since it is larger than the sum of its proper divisors (1).
142365664232497 is an equidigital number, since it uses as much as digits as its factorization.
142365664232497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 313528320, while the sum is 64.
The spelling of 142365664232497 in words is "one hundred forty-two trillion, three hundred sixty-five billion, six hundred sixty-four million, two hundred thirty-two thousand, four hundred ninety-seven".
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