Base | Representation |
---|---|
bin | 10100101110000000011… |
… | …101100101011001010010 |
3 | 12001010001022222020110011 |
4 | 110232000131211121102 |
5 | 141311410042221340 |
6 | 3010025124225134 |
7 | 204602554223050 |
oct | 24560035453122 |
9 | 5033038866404 |
10 | 1423789413970 |
11 | 4a990a0080a0 |
12 | 1abb3423b1aa |
13 | a43553b06a1 |
14 | 4cca9ca91d0 |
15 | 270819050ea |
hex | 14b80765652 |
1423789413970 has 64 divisors (see below), whose sum is σ = 3198581001216. Its totient is φ = 443309676480.
The previous prime is 1423789413961. The next prime is 1423789413979. The reversal of 1423789413970 is 793149873241.
It is an interprime number because it is at equal distance from previous prime (1423789413961) and next prime (1423789413979).
It is a super-3 number, since 3×14237894139703 (a number of 37 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (1423789413979) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 247092 + ... + 1705471.
It is an arithmetic number, because the mean of its divisors is an integer number (49977828144).
Almost surely, 21423789413970 is an apocalyptic number.
1423789413970 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1423789413970 is an abundant number, since it is smaller than the sum of its proper divisors (1774791587246).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1423789413970 is a wasteful number, since it uses less digits than its factorization.
1423789413970 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1953535.
The product of its (nonzero) digits is 9144576, while the sum is 58.
The spelling of 1423789413970 in words is "one trillion, four hundred twenty-three billion, seven hundred eighty-nine million, four hundred thirteen thousand, nine hundred seventy".
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