Base | Representation |
---|---|
bin | 11010100001101011… |
… | …00100000011110111 |
3 | 1100202111011212201112 |
4 | 31100311210003313 |
5 | 213131211324003 |
6 | 10313044345235 |
7 | 1012623345521 |
oct | 152065440367 |
9 | 40674155645 |
10 | 14241120503 |
11 | 6048817685 |
12 | 29153a521b |
13 | 145c562a2c |
14 | 991520a11 |
15 | 5853b13d8 |
hex | 350d640f7 |
14241120503 has 2 divisors, whose sum is σ = 14241120504. Its totient is φ = 14241120502.
The previous prime is 14241120499. The next prime is 14241120583. The reversal of 14241120503 is 30502114241.
14241120503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (30502114241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14241120503 - 22 = 14241120499 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14241120583) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7120560251 + 7120560252.
It is an arithmetic number, because the mean of its divisors is an integer number (7120560252).
Almost surely, 214241120503 is an apocalyptic number.
14241120503 is a deficient number, since it is larger than the sum of its proper divisors (1).
14241120503 is an equidigital number, since it uses as much as digits as its factorization.
14241120503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 14241120503 its reverse (30502114241), we get a palindrome (44743234744).
The spelling of 14241120503 in words is "fourteen billion, two hundred forty-one million, one hundred twenty thousand, five hundred three".
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