Base | Representation |
---|---|
bin | 1100111100111100010100… |
… | …0010010110001100100111 |
3 | 1212102102211022002120202112 |
4 | 3033033011002112030213 |
5 | 3331311304303003444 |
6 | 50142140431031235 |
7 | 2666613200242661 |
oct | 317170502261447 |
9 | 55372738076675 |
10 | 14241122312999 |
11 | 45a069830a22a |
12 | 172003706b51b |
13 | 7c3c169b94ba |
14 | 3733b9bc7531 |
15 | 19a69e64b69e |
hex | cf3c5096327 |
14241122312999 has 2 divisors, whose sum is σ = 14241122313000. Its totient is φ = 14241122312998.
The previous prime is 14241122312971. The next prime is 14241122313017. The reversal of 14241122312999 is 99921322114241.
14241122312999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (99921322114241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14241122312999 - 232 = 14236827345703 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14241122312399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7120561156499 + 7120561156500.
It is an arithmetic number, because the mean of its divisors is an integer number (7120561156500).
Almost surely, 214241122312999 is an apocalyptic number.
14241122312999 is a deficient number, since it is larger than the sum of its proper divisors (1).
14241122312999 is an equidigital number, since it uses as much as digits as its factorization.
14241122312999 is an evil number, because the sum of its binary digits is even.
The product of its digits is 559872, while the sum is 50.
The spelling of 14241122312999 in words is "fourteen trillion, two hundred forty-one billion, one hundred twenty-two million, three hundred twelve thousand, nine hundred ninety-nine".
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