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142412260547 is a prime number
BaseRepresentation
bin1000010010100001101…
…1101010010011000011
3111121120221210102010102
42010220123222103003
54313130014314142
6145231232553015
713201052145614
oct2045033522303
9447527712112
10142412260547
11554400101a7
12237256b276b
13105775813bb
146c6db5dc0b
153a878ba532
hex21286ea4c3

142412260547 has 2 divisors, whose sum is σ = 142412260548. Its totient is φ = 142412260546.

The previous prime is 142412260541. The next prime is 142412260567. The reversal of 142412260547 is 745062214241.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 142412260547 - 210 = 142412259523 is a prime.

It is a super-2 number, since 2×1424122605472 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 142412260547.

It is not a weakly prime, because it can be changed into another prime (142412260541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71206130273 + 71206130274.

It is an arithmetic number, because the mean of its divisors is an integer number (71206130274).

Almost surely, 2142412260547 is an apocalyptic number.

142412260547 is a deficient number, since it is larger than the sum of its proper divisors (1).

142412260547 is an equidigital number, since it uses as much as digits as its factorization.

142412260547 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 107520, while the sum is 38.

Adding to 142412260547 its reverse (745062214241), we get a palindrome (887474474788).

The spelling of 142412260547 in words is "one hundred forty-two billion, four hundred twelve million, two hundred sixty thousand, five hundred forty-seven".