Base | Representation |
---|---|
bin | 1000010010100001110… |
… | …0100101000101000101 |
3 | 111121120222020122101211 |
4 | 2010220130211011011 |
5 | 4313130100020232 |
6 | 145231242051421 |
7 | 13201054200562 |
oct | 2045034450505 |
9 | 447528218354 |
10 | 142412501317 |
11 | 55440165089 |
12 | 237257a9b71 |
13 | 10577636b78 |
14 | 6c6dbc3869 |
15 | 3a87916a47 |
hex | 2128725145 |
142412501317 has 2 divisors, whose sum is σ = 142412501318. Its totient is φ = 142412501316.
The previous prime is 142412501299. The next prime is 142412501377. The reversal of 142412501317 is 713105214241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 118794651556 + 23617849761 = 344666^2 + 153681^2 .
It is a cyclic number.
It is not a de Polignac number, because 142412501317 - 223 = 142404112709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142412501377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71206250658 + 71206250659.
It is an arithmetic number, because the mean of its divisors is an integer number (71206250659).
Almost surely, 2142412501317 is an apocalyptic number.
It is an amenable number.
142412501317 is a deficient number, since it is larger than the sum of its proper divisors (1).
142412501317 is an equidigital number, since it uses as much as digits as its factorization.
142412501317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 31.
Adding to 142412501317 its reverse (713105214241), we get a palindrome (855517715558).
The spelling of 142412501317 in words is "one hundred forty-two billion, four hundred twelve million, five hundred one thousand, three hundred seventeen".
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